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1200020110241 is a prime number
BaseRepresentation
bin10001011101100110110…
…001011011101110100001
311020201110110112211001012
4101131212301123232201
5124130120122011431
62315140455350305
7152461421431331
oct21354661335641
94221413484035
101200020110241
11422a20082227
121746a4382395
1389213809364
144211d0810c1
152133685e22b
hex11766c5bba1

1200020110241 has 2 divisors, whose sum is σ = 1200020110242. Its totient is φ = 1200020110240.

The previous prime is 1200020110169. The next prime is 1200020110243. The reversal of 1200020110241 is 1420110200021.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1194821700241 + 5198410000 = 1093079^2 + 72100^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1200020110241 is a prime.

Together with 1200020110243, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (1200020110243) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 600010055120 + 600010055121.

It is an arithmetic number, because the mean of its divisors is an integer number (600010055121).

Almost surely, 21200020110241 is an apocalyptic number.

It is an amenable number.

1200020110241 is a deficient number, since it is larger than the sum of its proper divisors (1).

1200020110241 is an equidigital number, since it uses as much as digits as its factorization.

1200020110241 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 32, while the sum is 14.

Adding to 1200020110241 its reverse (1420110200021), we get a palindrome (2620130310262).

The spelling of 1200020110241 in words is "one trillion, two hundred billion, twenty million, one hundred ten thousand, two hundred forty-one".