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1200020122241 is a prime number
BaseRepresentation
bin10001011101100110110…
…001011110101010000001
311020201110110120102111122
4101131212301132222001
5124130120122402431
62315140455522025
7152461421511323
oct21354661365201
94221413512448
101200020122241
11422a20090246
121746a4389315
1389213811965
144211d085613
1521336862a7b
hex11766c5ea81

1200020122241 has 2 divisors, whose sum is σ = 1200020122242. Its totient is φ = 1200020122240.

The previous prime is 1200020122199. The next prime is 1200020122243. The reversal of 1200020122241 is 1422210200021.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1155025227841 + 44994894400 = 1074721^2 + 212120^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1200020122241 is a prime.

Together with 1200020122243, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (1200020122243) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 600010061120 + 600010061121.

It is an arithmetic number, because the mean of its divisors is an integer number (600010061121).

Almost surely, 21200020122241 is an apocalyptic number.

It is an amenable number.

1200020122241 is a deficient number, since it is larger than the sum of its proper divisors (1).

1200020122241 is an equidigital number, since it uses as much as digits as its factorization.

1200020122241 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 128, while the sum is 17.

Adding to 1200020122241 its reverse (1422210200021), we get a palindrome (2622230322262).

The spelling of 1200020122241 in words is "one trillion, two hundred billion, twenty million, one hundred twenty-two thousand, two hundred forty-one".