Search a number
-
+
120002012342 = 260001006171
BaseRepresentation
bin110111111000010101…
…1010110010010110110
3102110202010221211220122
41233300223112102312
53431231003343332
6131043403331542
711445522163202
oct1576053262266
9373663854818
10120002012342
114699000a013
121b310520bb2
13b4157402c4
145b4570bb02
1531c5251c12
hex1bf0ad64b6

120002012342 has 4 divisors (see below), whose sum is σ = 180003018516. Its totient is φ = 60001006170.

The previous prime is 120002012341. The next prime is 120002012369. The reversal of 120002012342 is 243210200021.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 243210200021 = 863281819467.

It is a super-2 number, since 2×1200020123422 (a number of 23 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 120002012342.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (120002012341) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 30000503084 + ... + 30000503087.

It is an arithmetic number, because the mean of its divisors is an integer number (45000754629).

Almost surely, 2120002012342 is an apocalyptic number.

120002012342 is a deficient number, since it is larger than the sum of its proper divisors (60001006174).

120002012342 is an equidigital number, since it uses as much as digits as its factorization.

120002012342 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 60001006173.

The product of its (nonzero) digits is 192, while the sum is 17.

Adding to 120002012342 its reverse (243210200021), we get a palindrome (363212212363).

The spelling of 120002012342 in words is "one hundred twenty billion, two million, twelve thousand, three hundred forty-two".

Divisors: 1 2 60001006171 120002012342