Base | Representation |
---|---|
bin | 11011010010010000101011… |
… | …001001101001110010101011 |
3 | 120201220002102101111100112011 |
4 | 123102100223021221302223 |
5 | 111212103310202413003 |
6 | 1103120113001500351 |
7 | 34163603105455522 |
oct | 3322205311516253 |
9 | 521802371440464 |
10 | 120002110201003 |
11 | 3526667783a488 |
12 | 11561267aa16b7 |
13 | 51c61c5679a14 |
14 | 218c1c14134b9 |
15 | dd17e4a3546d |
hex | 6d242b269cab |
120002110201003 has 2 divisors, whose sum is σ = 120002110201004. Its totient is φ = 120002110201002.
The previous prime is 120002110200953. The next prime is 120002110201033. The reversal of 120002110201003 is 300102011200021.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 120002110201003 - 245 = 84817738112171 is a prime.
It is not a weakly prime, because it can be changed into another prime (120002110201033) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60001055100501 + 60001055100502.
It is an arithmetic number, because the mean of its divisors is an integer number (60001055100502).
Almost surely, 2120002110201003 is an apocalyptic number.
120002110201003 is a deficient number, since it is larger than the sum of its proper divisors (1).
120002110201003 is an equidigital number, since it uses as much as digits as its factorization.
120002110201003 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 24, while the sum is 13.
Adding to 120002110201003 its reverse (300102011200021), we get a palindrome (420104121401024).
The spelling of 120002110201003 in words is "one hundred twenty trillion, two billion, one hundred ten million, two hundred one thousand, three".
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