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12000221133 = 34000073711
BaseRepresentation
bin10110010110100010…
…01101011111001101
31010222022112101200120
423023101031133031
5144034024034013
65302434215153
7603243124305
oct131321153715
933868471616
1012000221133
1150a88a282a
1223aaa244b9
131193211384
1481ba78605
154a37b6123
hex2cb44d7cd

12000221133 has 4 divisors (see below), whose sum is σ = 16000294848. Its totient is φ = 8000147420.

The previous prime is 12000221131. The next prime is 12000221183. The reversal of 12000221133 is 33112200021.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 12000221133 - 21 = 12000221131 is a prime.

It is a Curzon number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (12000221131) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2000036853 + ... + 2000036858.

It is an arithmetic number, because the mean of its divisors is an integer number (4000073712).

Almost surely, 212000221133 is an apocalyptic number.

It is an amenable number.

12000221133 is a deficient number, since it is larger than the sum of its proper divisors (4000073715).

12000221133 is an equidigital number, since it uses as much as digits as its factorization.

12000221133 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 4000073714.

The product of its (nonzero) digits is 72, while the sum is 15.

Adding to 12000221133 its reverse (33112200021), we get a palindrome (45112421154).

The spelling of 12000221133 in words is "twelve billion, two hundred twenty-one thousand, one hundred thirty-three".

Divisors: 1 3 4000073711 12000221133