120002331300101 has 2 divisors, whose sum is σ = 120002331300102. Its totient is φ = 120002331300100.

The previous prime is 120002331300073. The next prime is 120002331300107. The reversal of 120002331300101 is 101003133200021.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 118347223320001 + 1655107980100 = 10878751^2 + 1286510^2 .

It is a cyclic number.

It is not a de Polignac number, because 120002331300101 - 2¹⁰ = 120002331299077 is a prime.

It is a super-2 number, since 2×120002331300101² (a number of 29 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 120002331300101.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (120002331300107) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60001165650050 + 60001165650051.

It is an arithmetic number, because the mean of its divisors is an integer number (60001165650051).

Almost surely, 2^{120002331300101} is an apocalyptic number.

It is an amenable number.

120002331300101 is a deficient number, since it is larger than the sum of its proper divisors (1).

120002331300101 is an equidigital number, since it uses as much as digits as its factorization.

120002331300101 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 108, while the sum is 17.

Adding to 120002331300101 its reverse (101003133200021), we get a palindrome (221005464500122).

The spelling of 120002331300101 in words is "one hundred twenty trillion, two billion, three hundred thirty-one million, three hundred thousand, one hundred one".