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12000477 = 34000159
BaseRepresentation
bin101101110001…
…110011011101
3211120200120010
4231301303131
511033003402
61105113433
7204000546
oct55616335
924520503
1012000477
116857155
124028879
132642298
1418454cd
1510c0a6c
hexb71cdd

12000477 has 4 divisors (see below), whose sum is σ = 16000640. Its totient is φ = 8000316.

The previous prime is 12000473. The next prime is 12000509. The reversal of 12000477 is 77400021.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 77400021 = 325800007.

It is not a de Polignac number, because 12000477 - 22 = 12000473 is a prime.

It is a super-2 number, since 2×120004772 = 288022896455058, which contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (12000473) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2000077 + ... + 2000082.

It is an arithmetic number, because the mean of its divisors is an integer number (4000160).

Almost surely, 212000477 is an apocalyptic number.

It is an amenable number.

12000477 is a deficient number, since it is larger than the sum of its proper divisors (4000163).

12000477 is an equidigital number, since it uses as much as digits as its factorization.

12000477 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 4000162.

The product of its (nonzero) digits is 392, while the sum is 21.

The square root of 12000477 is about 3464.1704634732. The cubic root of 12000477 is about 228.9458819632.

Adding to 12000477 its reverse (77400021), we get a palindrome (89400498).

The spelling of 12000477 in words is "twelve million, four hundred seventy-seven", and thus it is an aban number.

Divisors: 1 3 4000159 12000477