Base | Representation |
---|---|
bin | 11011010010011000000001… |
… | …100010100001010000000111 |
3 | 120201220211210101022211211121 |
4 | 123102120001202201100013 |
5 | 111212220441003324033 |
6 | 1103123500034414411 |
7 | 34164302503653406 |
oct | 3322300142412007 |
9 | 521824711284747 |
10 | 120010002011143 |
11 | 35269a57532222 |
12 | 115628aaa31407 |
13 | 51c6b8266c66a |
14 | 218c72d59763d |
15 | dd1b077ae62d |
hex | 6d26018a1407 |
120010002011143 has 2 divisors, whose sum is σ = 120010002011144. Its totient is φ = 120010002011142.
The previous prime is 120010002011087. The next prime is 120010002011189. The reversal of 120010002011143 is 341110200010021.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 120010002011143 - 213 = 120010002002951 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (120010002015143) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60005001005571 + 60005001005572.
It is an arithmetic number, because the mean of its divisors is an integer number (60005001005572).
Almost surely, 2120010002011143 is an apocalyptic number.
120010002011143 is a deficient number, since it is larger than the sum of its proper divisors (1).
120010002011143 is an equidigital number, since it uses as much as digits as its factorization.
120010002011143 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 48, while the sum is 16.
Adding to 120010002011143 its reverse (341110200010021), we get a palindrome (461120202021164).
The spelling of 120010002011143 in words is "one hundred twenty trillion, ten billion, two million, eleven thousand, one hundred forty-three".
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