Base | Representation |
---|---|
bin | 1010111010100011010010… |
… | …0010100110010111101001 |
3 | 1120111021201201121002001220 |
4 | 2232220310202212113221 |
5 | 3033111042122012223 |
6 | 41305105330332253 |
7 | 2346021315552033 |
oct | 256506442462751 |
9 | 46437651532056 |
10 | 12001020110313 |
11 | 3907670a93883 |
12 | 1419a6542a089 |
13 | 6908cab4b460 |
14 | 2d6bd1282c53 |
15 | 15c2927756e3 |
hex | aea348a65e9 |
12001020110313 has 32 divisors (see below), whose sum is σ = 17498170776576. Its totient is φ = 7271380404288.
The previous prime is 12001020110237. The next prime is 12001020110333. The reversal of 12001020110313 is 31301102010021.
It is a happy number.
12001020110313 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is not a de Polignac number, because 12001020110313 - 224 = 12001003333097 is a prime.
It is a super-3 number, since 3×120010201103133 (a number of 40 digits) contains 333 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 12001020110292 and 12001020110301.
It is not an unprimeable number, because it can be changed into a prime (12001020110333) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 4087356 + ... + 6380322.
It is an arithmetic number, because the mean of its divisors is an integer number (546817836768).
Almost surely, 212001020110313 is an apocalyptic number.
12001020110313 is a gapful number since it is divisible by the number (13) formed by its first and last digit.
It is an amenable number.
12001020110313 is a deficient number, since it is larger than the sum of its proper divisors (5497150666263).
12001020110313 is a wasteful number, since it uses less digits than its factorization.
12001020110313 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2295053.
The product of its (nonzero) digits is 36, while the sum is 15.
Adding to 12001020110313 its reverse (31301102010021), we get a palindrome (43302122120334).
The spelling of 12001020110313 in words is "twelve trillion, one billion, twenty million, one hundred ten thousand, three hundred thirteen".
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