Base | Representation |
---|---|
bin | 11011010010011001111000… |
… | …110000010000101101111101 |
3 | 120201221000221202211222212222 |
4 | 123102121320300100231331 |
5 | 111212234040014232031 |
6 | 1103124430323335125 |
7 | 34164403201314452 |
oct | 3322317060205575 |
9 | 521830852758788 |
10 | 120012002102141 |
11 | 3526a893531196 |
12 | 115631688214a5 |
13 | 51c7110b49266 |
14 | 218c87d077829 |
15 | dd1bc318de7b |
hex | 6d2678c10b7d |
120012002102141 has 2 divisors, whose sum is σ = 120012002102142. Its totient is φ = 120012002102140.
The previous prime is 120012002102093. The next prime is 120012002102219. The reversal of 120012002102141 is 141201200210021.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 116144698932025 + 3867303170116 = 10777045^2 + 1966546^2 .
It is a cyclic number.
It is not a de Polignac number, because 120012002102141 - 26 = 120012002102077 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (120012002102341) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60006001051070 + 60006001051071.
It is an arithmetic number, because the mean of its divisors is an integer number (60006001051071).
Almost surely, 2120012002102141 is an apocalyptic number.
It is an amenable number.
120012002102141 is a deficient number, since it is larger than the sum of its proper divisors (1).
120012002102141 is an equidigital number, since it uses as much as digits as its factorization.
120012002102141 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 64, while the sum is 17.
Adding to 120012002102141 its reverse (141201200210021), we get a palindrome (261213202312162).
The spelling of 120012002102141 in words is "one hundred twenty trillion, twelve billion, two million, one hundred two thousand, one hundred forty-one".
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