12001200313231 has 4 divisors (see below), whose sum is σ = 12632842435000. Its totient is φ = 11369558191464.

The previous prime is 12001200313213. The next prime is 12001200313247. The reversal of 12001200313231 is 13231300210021.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 12001200313231 - 2¹⁷ = 12001200182159 is a prime.

It is a super-2 number, since 2×12001200313231² (a number of 27 digits) contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (19), and also a Moran number because the ratio is a prime number: 631642121749 = 12001200313231 / (1 + 2 + 0 + 0 + 1 + 2 + 0 + 0 + 3 + 1 + 3 + 2 + 3 + 1).

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 12001200313199 and 12001200313208.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (12001200313031) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 315821060856 + ... + 315821060893.

It is an arithmetic number, because the mean of its divisors is an integer number (3158210608750).

Almost surely, 2^{12001200313231} is an apocalyptic number.

12001200313231 is a deficient number, since it is larger than the sum of its proper divisors (631642121769).

12001200313231 is an equidigital number, since it uses as much as digits as its factorization.

12001200313231 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 631642121768.

The product of its (nonzero) digits is 216, while the sum is 19.

Adding to 12001200313231 its reverse (13231300210021), we get a palindrome (25232500523252).

The spelling of 12001200313231 in words is "twelve trillion, one billion, two hundred million, three hundred thirteen thousand, two hundred thirty-one".