Base | Representation |
---|---|
bin | 11011010010011001111110… |
… | …100110000101111110110111 |
3 | 120201221001012121020210201011 |
4 | 123102121332212011332313 |
5 | 111212234240111200043 |
6 | 1103124444144013051 |
7 | 34164405501300535 |
oct | 3322317646057667 |
9 | 521831177223634 |
10 | 120012100100023 |
11 | 3526a93388547a |
12 | 11563195601187 |
13 | 51c712823b681 |
14 | 218c88c0a7155 |
15 | dd1bcba9a59d |
hex | 6d267e985fb7 |
120012100100023 has 2 divisors, whose sum is σ = 120012100100024. Its totient is φ = 120012100100022.
The previous prime is 120012100099939. The next prime is 120012100100027. The reversal of 120012100100023 is 320001001210021.
It is a strong prime.
It is an emirp because it is prime and its reverse (320001001210021) is a distict prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-120012100100023 is a prime.
It is a super-3 number, since 3×1200121001000233 (a number of 43 digits) contains 333 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 120012100099976 and 120012100100012.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (120012100100027) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (29) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60006050050011 + 60006050050012.
It is an arithmetic number, because the mean of its divisors is an integer number (60006050050012).
Almost surely, 2120012100100023 is an apocalyptic number.
120012100100023 is a deficient number, since it is larger than the sum of its proper divisors (1).
120012100100023 is an equidigital number, since it uses as much as digits as its factorization.
120012100100023 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 24, while the sum is 13.
Adding to 120012100100023 its reverse (320001001210021), we get a palindrome (440013101310044).
The spelling of 120012100100023 in words is "one hundred twenty trillion, twelve billion, one hundred million, one hundred thousand, twenty-three".
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