Base | Representation |
---|---|
bin | 11011010010011010001010… |
… | …100101101010010001101101 |
3 | 120201221001201121212111012120 |
4 | 123102122022211222101231 |
5 | 111212240143114010013 |
6 | 1103124520132423153 |
7 | 34164413463466635 |
oct | 3322321245522155 |
9 | 521831647774176 |
10 | 120012301313133 |
11 | 3526aa274168a9 |
12 | 11563230a77ab9 |
13 | 51c715ab2bb98 |
14 | 218c8aaac36c5 |
15 | dd1bde594123 |
hex | 6d268a96a46d |
120012301313133 has 4 divisors (see below), whose sum is σ = 160016401750848. Its totient is φ = 80008200875420.
The previous prime is 120012301313083. The next prime is 120012301313141. The reversal of 120012301313133 is 331313103210021.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 120012301313133 - 210 = 120012301312109 is a prime.
It is a super-2 number, since 2×1200123013131332 (a number of 29 digits) contains 22 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (120012301313183) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 20002050218853 + ... + 20002050218858.
It is an arithmetic number, because the mean of its divisors is an integer number (40004100437712).
Almost surely, 2120012301313133 is an apocalyptic number.
It is an amenable number.
120012301313133 is a deficient number, since it is larger than the sum of its proper divisors (40004100437715).
120012301313133 is an equidigital number, since it uses as much as digits as its factorization.
120012301313133 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 40004100437714.
The product of its (nonzero) digits is 972, while the sum is 24.
Adding to 120012301313133 its reverse (331313103210021), we get a palindrome (451325404523154).
The spelling of 120012301313133 in words is "one hundred twenty trillion, twelve billion, three hundred one million, three hundred thirteen thousand, one hundred thirty-three".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.070 sec. • engine limits •