Base | Representation |
---|---|
bin | 11011010010011010111100… |
… | …001111010111101000100100 |
3 | 120201221010212200100011002002 |
4 | 123102122330033113220210 |
5 | 111212243344342033104 |
6 | 1103125134531104432 |
7 | 34164443230146500 |
oct | 3322327417275044 |
9 | 521833780304062 |
10 | 120013134330404 |
11 | 35270314659027 |
12 | 11563423a42118 |
13 | 51c72615a2203 |
14 | 218c9495a5300 |
15 | dd1c3c78e01e |
hex | 6d26bc3d7a24 |
120013134330404 has 36 divisors (see below), whose sum is σ = 244313079811164. Its totient is φ = 51434068262976.
The previous prime is 120013134330373. The next prime is 120013134330407. The reversal of 120013134330404 is 404033431310021.
It is a happy number.
It can be written as a sum of positive squares in 2 ways, for example, as 105848088062500 + 14165046267904 = 10288250^2 + 3763648^2 .
It is a super-2 number, since 2×1200131343304042 (a number of 29 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (120013134330407) by changing a digit.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 137866262 + ... + 138734034.
It is an arithmetic number, because the mean of its divisors is an integer number (6786474439199).
Almost surely, 2120013134330404 is an apocalyptic number.
120013134330404 is a gapful number since it is divisible by the number (14) formed by its first and last digit.
It is an amenable number.
120013134330404 is an abundant number, since it is smaller than the sum of its proper divisors (124299945480760).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
120013134330404 is a wasteful number, since it uses less digits than its factorization.
120013134330404 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1573404 (or 1573395 counting only the distinct ones).
The product of its (nonzero) digits is 10368, while the sum is 29.
Adding to 120013134330404 its reverse (404033431310021), we get a palindrome (524046565640425).
The spelling of 120013134330404 in words is "one hundred twenty trillion, thirteen billion, one hundred thirty-four million, three hundred thirty thousand, four hundred four".
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