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120014311332334 = 260007155666167
BaseRepresentation
bin11011010010011100000010…
…011001010001100111101110
3120201221020220201002001012011
4123102130002121101213232
5111212303302200113314
61103125451414231434
734164514341411136
oct3322340231214756
9521836821061164
10120014311332334
1135270868a86aa1
12115636b205557a
1351c73bb3a3763
14218ca1ba29ac6
15dd1caac854c4
hex6d27026519ee

120014311332334 has 4 divisors (see below), whose sum is σ = 180021466998504. Its totient is φ = 60007155666166.

The previous prime is 120014311332229. The next prime is 120014311332359. The reversal of 120014311332334 is 433233113410021.

It is a semiprime because it is the product of two primes.

It is a junction number, because it is equal to n+sod(n) for n = 120014311332296 and 120014311332305.

It is a congruent number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 30003577833082 + ... + 30003577833085.

It is an arithmetic number, because the mean of its divisors is an integer number (45005366749626).

Almost surely, 2120014311332334 is an apocalyptic number.

120014311332334 is a deficient number, since it is larger than the sum of its proper divisors (60007155666170).

120014311332334 is an equidigital number, since it uses as much as digits as its factorization.

120014311332334 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 60007155666169.

The product of its (nonzero) digits is 15552, while the sum is 31.

Adding to 120014311332334 its reverse (433233113410021), we get a palindrome (553247424742355).

The spelling of 120014311332334 in words is "one hundred twenty trillion, fourteen billion, three hundred eleven million, three hundred thirty-two thousand, three hundred thirty-four".

Divisors: 1 2 60007155666167 120014311332334