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120020301013121 = 196316857948059
BaseRepresentation
bin11011010010100001100111…
…011010000110000010000001
3120201221211101010201100120022
4123102201213122012002001
5111212403034024404441
61103132322022023225
734165115642020265
oct3322414732060201
9521854333640508
10120020301013121
1135273361aa9903
12115648a3b77b15
1351c7b34298582
14218d0293100a5
15dd200ba3084b
hex6d2867686081

120020301013121 has 4 divisors (see below), whose sum is σ = 126337158961200. Its totient is φ = 113703443065044.

The previous prime is 120020301013061. The next prime is 120020301013133. The reversal of 120020301013121 is 121310103020021.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-120020301013121 is a prime.

It is a super-3 number, since 3×1200203010131213 (a number of 43 digits) contains 333 as substring.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 120020301013121.

It is not an unprimeable number, because it can be changed into a prime (120020301013021) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3158428974011 + ... + 3158428974048.

It is an arithmetic number, because the mean of its divisors is an integer number (31584289740300).

Almost surely, 2120020301013121 is an apocalyptic number.

It is an amenable number.

120020301013121 is a deficient number, since it is larger than the sum of its proper divisors (6316857948079).

120020301013121 is an equidigital number, since it uses as much as digits as its factorization.

120020301013121 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 6316857948078.

The product of its (nonzero) digits is 72, while the sum is 17.

Adding to 120020301013121 its reverse (121310103020021), we get a palindrome (241330404033142).

The spelling of 120020301013121 in words is "one hundred twenty trillion, twenty billion, three hundred one million, thirteen thousand, one hundred twenty-one".

Divisors: 1 19 6316857948059 120020301013121