120021021213 has 4 divisors (see below), whose sum is σ = 160028028288. Its totient is φ = 80014014140.

The previous prime is 120021021193. The next prime is 120021021247. The reversal of 120021021213 is 312120120021.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 312120120021 = 3 ⋅104040040007.

It is a cyclic number.

It is not a de Polignac number, because 120021021213 - 2²⁶ = 119953912349 is a prime.

It is a super-2 number, since 2×120021021213² (a number of 23 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 120021021192 and 120021021201.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (120021021293) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 20003503533 + ... + 20003503538.

It is an arithmetic number, because the mean of its divisors is an integer number (40007007072).

Almost surely, 2^120021021213 is an apocalyptic number.

It is an amenable number.

120021021213 is a deficient number, since it is larger than the sum of its proper divisors (40007007075).

120021021213 is an equidigital number, since it uses as much as digits as its factorization.

120021021213 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 40007007074.

The product of its (nonzero) digits is 48, while the sum is 15.

Adding to 120021021213 its reverse (312120120021), we get a palindrome (432141141234).

The spelling of 120021021213 in words is "one hundred twenty billion, twenty-one million, twenty-one thousand, two hundred thirteen".