Base | Representation |
---|---|
bin | 10110010110110000… |
… | …11011011001001111 |
3 | 1010222110002111222112 |
4 | 23023120123121033 |
5 | 144040020104403 |
6 | 5302542534235 |
7 | 603265164251 |
oct | 131330333117 |
9 | 33873074875 |
10 | 12002113103 |
11 | 50a9975242 |
12 | 23ab59737b |
13 | 1193724596 |
14 | 81c00bcd1 |
15 | 4a3a3b9d8 |
hex | 2cb61b64f |
12002113103 has 4 divisors (see below), whose sum is σ = 12120946008. Its totient is φ = 11883280200.
The previous prime is 12002113099. The next prime is 12002113127. The reversal of 12002113103 is 30131120021.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 12002113103 - 22 = 12002113099 is a prime.
It is a super-4 number, since 4×120021131034 (a number of 41 digits) contains 4444 as substring.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (12002113163) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 59416301 + ... + 59416502.
It is an arithmetic number, because the mean of its divisors is an integer number (3030236502).
Almost surely, 212002113103 is an apocalyptic number.
12002113103 is a deficient number, since it is larger than the sum of its proper divisors (118832905).
12002113103 is a wasteful number, since it uses less digits than its factorization.
12002113103 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 118832904.
The product of its (nonzero) digits is 36, while the sum is 14.
Adding to 12002113103 its reverse (30131120021), we get a palindrome (42133233124).
The spelling of 12002113103 in words is "twelve billion, two million, one hundred thirteen thousand, one hundred three".
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