Base | Representation |
---|---|
bin | 11011010010100011001101… |
… | …010101001011010100001111 |
3 | 120201221222210022100200200121 |
4 | 123102203031111023110033 |
5 | 111212420034304000304 |
6 | 1103133203425005411 |
7 | 34165206214456066 |
oct | 3322431525132417 |
9 | 521858708320617 |
10 | 120022011000079 |
11 | 3527405a273371 |
12 | 115650a0783867 |
13 | 51c8047630786 |
14 | 218d14c4751dd |
15 | dd20abc08554 |
hex | 6d28cd54b50f |
120022011000079 has 2 divisors, whose sum is σ = 120022011000080. Its totient is φ = 120022011000078.
The previous prime is 120022011000071. The next prime is 120022011000131. The reversal of 120022011000079 is 970000110220021.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 120022011000079 - 23 = 120022011000071 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (120022011000071) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60011005500039 + 60011005500040.
It is an arithmetic number, because the mean of its divisors is an integer number (60011005500040).
Almost surely, 2120022011000079 is an apocalyptic number.
120022011000079 is a deficient number, since it is larger than the sum of its proper divisors (1).
120022011000079 is an equidigital number, since it uses as much as digits as its factorization.
120022011000079 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 504, while the sum is 25.
The spelling of 120022011000079 in words is "one hundred twenty trillion, twenty-two billion, eleven million, seventy-nine", and thus it is an aban number.
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.071 sec. • engine limits •