Base | Representation |
---|---|
bin | 11011010010100011001101… |
… | …010101001011010101000011 |
3 | 120201221222210022100200202112 |
4 | 123102203031111023111003 |
5 | 111212420034304001011 |
6 | 1103133203425005535 |
7 | 34165206214456202 |
oct | 3322431525132503 |
9 | 521858708320675 |
10 | 120022011000131 |
11 | 3527405a273409 |
12 | 115650a07838ab |
13 | 51c80476307c6 |
14 | 218d14c475239 |
15 | dd20abc0858b |
hex | 6d28cd54b543 |
120022011000131 has 2 divisors, whose sum is σ = 120022011000132. Its totient is φ = 120022011000130.
The previous prime is 120022011000079. The next prime is 120022011000139. The reversal of 120022011000131 is 131000110220021.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 120022011000131 - 238 = 119747133093187 is a prime.
It is a super-2 number, since 2×1200220110001312 (a number of 29 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (120022011000139) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60011005500065 + 60011005500066.
It is an arithmetic number, because the mean of its divisors is an integer number (60011005500066).
Almost surely, 2120022011000131 is an apocalyptic number.
120022011000131 is a deficient number, since it is larger than the sum of its proper divisors (1).
120022011000131 is an equidigital number, since it uses as much as digits as its factorization.
120022011000131 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 24, while the sum is 14.
Adding to 120022011000131 its reverse (131000110220021), we get a palindrome (251022121220152).
The spelling of 120022011000131 in words is "one hundred twenty trillion, twenty-two billion, eleven million, one hundred thirty-one", and thus it is an aban number.
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