Search a number
-
+
120022011000131 is a prime number
BaseRepresentation
bin11011010010100011001101…
…010101001011010101000011
3120201221222210022100200202112
4123102203031111023111003
5111212420034304001011
61103133203425005535
734165206214456202
oct3322431525132503
9521858708320675
10120022011000131
113527405a273409
12115650a07838ab
1351c80476307c6
14218d14c475239
15dd20abc0858b
hex6d28cd54b543

120022011000131 has 2 divisors, whose sum is σ = 120022011000132. Its totient is φ = 120022011000130.

The previous prime is 120022011000079. The next prime is 120022011000139. The reversal of 120022011000131 is 131000110220021.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 120022011000131 - 238 = 119747133093187 is a prime.

It is a super-2 number, since 2×1200220110001312 (a number of 29 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (120022011000139) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60011005500065 + 60011005500066.

It is an arithmetic number, because the mean of its divisors is an integer number (60011005500066).

Almost surely, 2120022011000131 is an apocalyptic number.

120022011000131 is a deficient number, since it is larger than the sum of its proper divisors (1).

120022011000131 is an equidigital number, since it uses as much as digits as its factorization.

120022011000131 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 24, while the sum is 14.

Adding to 120022011000131 its reverse (131000110220021), we get a palindrome (251022121220152).

The spelling of 120022011000131 in words is "one hundred twenty trillion, twenty-two billion, eleven million, one hundred thirty-one", and thus it is an aban number.