Base | Representation |
---|---|
bin | 1010111010100111101011… |
… | …1011101101111011110111 |
3 | 1120111101210000211120101112 |
4 | 2232221322323231323313 |
5 | 3033121001440200043 |
6 | 41305422435145235 |
7 | 2346062506032521 |
oct | 256517273557367 |
9 | 46441700746345 |
10 | 12002201100023 |
11 | 3908117695932 |
12 | 141a134a4521b |
13 | 690a58717b34 |
14 | 2d6ca4064a11 |
15 | 15c3112a8518 |
hex | aea7aeedef7 |
12002201100023 has 8 divisors (see below), whose sum is σ = 12126523999968. Its totient is φ = 11877890217984.
The previous prime is 12002201099923. The next prime is 12002201100049. The reversal of 12002201100023 is 32000110220021.
It is a happy number.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 12002201100023 - 216 = 12002201034487 is a prime.
It is a super-2 number, since 2×120022011000232 (a number of 27 digits) contains 22 as substring.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 12002201099980 and 12002201100007.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (12002201100053) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (31) of ones.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 989786 + ... + 4998407.
It is an arithmetic number, because the mean of its divisors is an integer number (1515815499996).
Almost surely, 212002201100023 is an apocalyptic number.
12002201100023 is a deficient number, since it is larger than the sum of its proper divisors (124322899945).
12002201100023 is an equidigital number, since it uses as much as digits as its factorization.
12002201100023 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 6008953.
The product of its (nonzero) digits is 48, while the sum is 14.
Adding to 12002201100023 its reverse (32000110220021), we get a palindrome (44002311320044).
The spelling of 12002201100023 in words is "twelve trillion, two billion, two hundred one million, one hundred thousand, twenty-three".
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