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120023302200103 = 251478180486853
BaseRepresentation
bin11011010010100100011010…
…010010101101101100100111
3120201222010010021222110010201
4123102210122102231230213
5111212430210330400403
61103133535511531331
734165253213465461
oct3322443222555447
9521863107873121
10120023302200103
1135274662100025
12115653a1089b47
1351c81c1ca7163
14218d231b45131
15dd213525b21d
hex6d291a4adb27

120023302200103 has 4 divisors (see below), whose sum is σ = 120501482687208. Its totient is φ = 119545121713000.

The previous prime is 120023302200083. The next prime is 120023302200119. The reversal of 120023302200103 is 301002203320021.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 120023302200103 - 217 = 120023302069031 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (120023302200133) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 239090243176 + ... + 239090243677.

It is an arithmetic number, because the mean of its divisors is an integer number (30125370671802).

Almost surely, 2120023302200103 is an apocalyptic number.

120023302200103 is a deficient number, since it is larger than the sum of its proper divisors (478180487105).

120023302200103 is an equidigital number, since it uses as much as digits as its factorization.

120023302200103 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 478180487104.

The product of its (nonzero) digits is 432, while the sum is 19.

Adding to 120023302200103 its reverse (301002203320021), we get a palindrome (421025505520124).

The spelling of 120023302200103 in words is "one hundred twenty trillion, twenty-three billion, three hundred two million, two hundred thousand, one hundred three".

Divisors: 1 251 478180486853 120023302200103