Base | Representation |
---|---|
bin | 10001011101110011100… |
… | …111010010010101010100 |
3 | 11020202000110221111111120 |
4 | 101131303213102111110 |
5 | 124131040300213012 |
6 | 2315214113203540 |
7 | 152466645610536 |
oct | 21356347222524 |
9 | 4222013844446 |
10 | 1200235554132 |
11 | 42302075342a |
12 | 1747445605b0 |
13 | 89249340054 |
14 | 4213d923856 |
15 | 2134a71958c |
hex | 117739d2554 |
1200235554132 has 12 divisors (see below), whose sum is σ = 2800549626336. Its totient is φ = 400078518040.
The previous prime is 1200235554079. The next prime is 1200235554173. The reversal of 1200235554132 is 2314555320021.
It is a tau number, because it is divible by the number of its divisors (12).
It is a junction number, because it is equal to n+sod(n) for n = 1200235554093 and 1200235554102.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 50009814744 + ... + 50009814767.
It is an arithmetic number, because the mean of its divisors is an integer number (233379135528).
Almost surely, 21200235554132 is an apocalyptic number.
1200235554132 is a gapful number since it is divisible by the number (12) formed by its first and last digit.
It is an amenable number.
1200235554132 is an abundant number, since it is smaller than the sum of its proper divisors (1600314072204).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
1200235554132 is a wasteful number, since it uses less digits than its factorization.
1200235554132 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 100019629518 (or 100019629516 counting only the distinct ones).
The product of its (nonzero) digits is 36000, while the sum is 33.
The spelling of 1200235554132 in words is "one trillion, two hundred billion, two hundred thirty-five million, five hundred fifty-four thousand, one hundred thirty-two".
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