Base | Representation |
---|---|
bin | 11011010010100110001110… |
… | …000111100001001111000101 |
3 | 120201222022010201111101011211 |
4 | 123102212032013201033011 |
5 | 111212443200312010113 |
6 | 1103134500405531421 |
7 | 34165352320554133 |
oct | 3322461607411705 |
9 | 521868121441154 |
10 | 120025245422533 |
11 | 35275469a97880 |
12 | 11565843a13b71 |
13 | 51c8441762209 |
14 | 218d377c60753 |
15 | dd21eab55b3d |
hex | 6d298e1e13c5 |
120025245422533 has 16 divisors (see below), whose sum is σ = 130987279374336. Its totient is φ = 109071655997440.
The previous prime is 120025245422513. The next prime is 120025245422569. The reversal of 120025245422533 is 335224542520021.
It is a cyclic number.
It is not a de Polignac number, because 120025245422533 - 217 = 120025245291461 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (120025245422513) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 944251260 + ... + 944378362.
It is an arithmetic number, because the mean of its divisors is an integer number (8186704960896).
Almost surely, 2120025245422533 is an apocalyptic number.
It is an amenable number.
120025245422533 is a deficient number, since it is larger than the sum of its proper divisors (10962033951803).
120025245422533 is a wasteful number, since it uses less digits than its factorization.
120025245422533 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 159644.
The product of its (nonzero) digits is 576000, while the sum is 40.
Adding to 120025245422533 its reverse (335224542520021), we get a palindrome (455249787942554).
The spelling of 120025245422533 in words is "one hundred twenty trillion, twenty-five billion, two hundred forty-five million, four hundred twenty-two thousand, five hundred thirty-three".
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