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12003102200103 = 37571576295243
BaseRepresentation
bin1010111010101011000010…
…1001001001000100100111
31120111111002211102012022120
42232222300221021010213
53033124323130400403
641310052105001023
72346124030202460
oct256526051110447
946444084365276
1012003102200103
11390853a2a9743
12141a346783173
13690b70308151
142d6d4b9c9d67
1515c365450e53
hexaeab0a49127

12003102200103 has 8 divisors (see below), whose sum is σ = 18290441447808. Its totient is φ = 6858915542904.

The previous prime is 12003102200093. The next prime is 12003102200137. The reversal of 12003102200103 is 30100220130021.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 12003102200103 - 24 = 12003102200087 is a prime.

It is a super-2 number, since 2×120031022001032 (a number of 27 digits) contains 22 as substring.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (12003102200203) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 285788147601 + ... + 285788147642.

It is an arithmetic number, because the mean of its divisors is an integer number (2286305180976).

Almost surely, 212003102200103 is an apocalyptic number.

12003102200103 is a deficient number, since it is larger than the sum of its proper divisors (6287339247705).

12003102200103 is an equidigital number, since it uses as much as digits as its factorization.

12003102200103 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 571576295253.

The product of its (nonzero) digits is 72, while the sum is 15.

Adding to 12003102200103 its reverse (30100220130021), we get a palindrome (42103322330124).

The spelling of 12003102200103 in words is "twelve trillion, three billion, one hundred two million, two hundred thousand, one hundred three".

Divisors: 1 3 7 21 571576295243 1714728885729 4001034066701 12003102200103