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12003111493 is a prime number
BaseRepresentation
bin10110010110111000…
…01111001001000101
31010222111222020111221
423023130033021011
5144040244031433
65303020200341
7603306523102
oct131334171105
933874866457
1012003111493
1150aa49735a
1223ab9990b1
1311939b3b49
1481c1cbaa9
154a3b8772d
hex2cb70f245

12003111493 has 2 divisors, whose sum is σ = 12003111494. Its totient is φ = 12003111492.

The previous prime is 12003111467. The next prime is 12003111553. The reversal of 12003111493 is 39411130021.

12003111493 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 6126662529 + 5876448964 = 78273^2 + 76658^2 .

It is an emirp because it is prime and its reverse (39411130021) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 12003111493 - 217 = 12002980421 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (12003111413) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6001555746 + 6001555747.

It is an arithmetic number, because the mean of its divisors is an integer number (6001555747).

Almost surely, 212003111493 is an apocalyptic number.

It is an amenable number.

12003111493 is a deficient number, since it is larger than the sum of its proper divisors (1).

12003111493 is an equidigital number, since it uses as much as digits as its factorization.

12003111493 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 648, while the sum is 25.

The spelling of 12003111493 in words is "twelve billion, three million, one hundred eleven thousand, four hundred ninety-three".