12003120333121 has 2 divisors, whose sum is σ = 12003120333122. Its totient is φ = 12003120333120.

The previous prime is 12003120333119. The next prime is 12003120333143. The reversal of 12003120333121 is 12133302130021.

It is an a-pointer prime, because the next prime (12003120333143) can be obtained adding 12003120333121 to its sum of digits (22).

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 11423291386896 + 579828946225 = 3379836^2 + 761465^2 .

It is a cyclic number.

It is not a de Polignac number, because 12003120333121 - 2¹ = 12003120333119 is a prime.

Together with 12003120333119, it forms a pair of twin primes.

It is a junction number, because it is equal to n+sod(n) for n = 12003120333092 and 12003120333101.

It is not a weakly prime, because it can be changed into another prime (12003120331121) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6001560166560 + 6001560166561.

It is an arithmetic number, because the mean of its divisors is an integer number (6001560166561).

Almost surely, 2^{12003120333121} is an apocalyptic number.

It is an amenable number.

12003120333121 is a deficient number, since it is larger than the sum of its proper divisors (1).

12003120333121 is an equidigital number, since it uses as much as digits as its factorization.

12003120333121 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 648, while the sum is 22.

Adding to 12003120333121 its reverse (12133302130021), we get a palindrome (24136422463142).

The spelling of 12003120333121 in words is "twelve trillion, three billion, one hundred twenty million, three hundred thirty-three thousand, one hundred twenty-one".