Base | Representation |
---|---|
bin | 10001011101111000001… |
… | …011010111011111110101 |
3 | 11020202012211000111221211 |
4 | 101131320023113133311 |
5 | 124131214400340313 |
6 | 2315225450241421 |
7 | 152501565455533 |
oct | 21357013273765 |
9 | 4222184014854 |
10 | 1200312121333 |
11 | 42305a99a506 |
12 | 174766126271 |
13 | 8925c16aaa0 |
14 | 42149b75153 |
15 | 213522e0e3d |
hex | 117782d77f5 |
1200312121333 has 8 divisors (see below), whose sum is σ = 1292720407776. Its totient is φ = 1107914775600.
The previous prime is 1200312121313. The next prime is 1200312121339. The reversal of 1200312121333 is 3331212130021.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 1200312121333 - 213 = 1200312113141 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1200312121339) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 2506603 + ... + 2946808.
It is an arithmetic number, because the mean of its divisors is an integer number (161590050972).
Almost surely, 21200312121333 is an apocalyptic number.
1200312121333 is a gapful number since it is divisible by the number (13) formed by its first and last digit.
It is an amenable number.
1200312121333 is a deficient number, since it is larger than the sum of its proper divisors (92408286443).
1200312121333 is a wasteful number, since it uses less digits than its factorization.
1200312121333 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 5470355.
The product of its (nonzero) digits is 648, while the sum is 22.
Adding to 1200312121333 its reverse (3331212130021), we get a palindrome (4531524251354).
The spelling of 1200312121333 in words is "one trillion, two hundred billion, three hundred twelve million, one hundred twenty-one thousand, three hundred thirty-three".
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