Base | Representation |
---|---|
bin | 1010111010101011000111… |
… | …0010000011010101011000 |
3 | 1120111111011011101020102210 |
4 | 2232222301302003111120 |
5 | 3033124343024004422 |
6 | 41310054030355120 |
7 | 2346124351515516 |
oct | 256526162032530 |
9 | 46444134336383 |
10 | 12003121313112 |
11 | 390854a073616 |
12 | 141a35105baa0 |
13 | 690b7426a917 |
14 | 2d6d503634b6 |
15 | 15c366e7910c |
hex | aeab1c83558 |
12003121313112 has 32 divisors (see below), whose sum is σ = 30344969617200. Its totient is φ = 3956084926464.
The previous prime is 12003121313083. The next prime is 12003121313119. The reversal of 12003121313112 is 21131312130021.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (12003121313119) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 2809717273 + ... + 2809721544.
Almost surely, 212003121313112 is an apocalyptic number.
12003121313112 is a gapful number since it is divisible by the number (12) formed by its first and last digit.
It is an amenable number.
12003121313112 is an abundant number, since it is smaller than the sum of its proper divisors (18341848304088).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
12003121313112 is a wasteful number, since it uses less digits than its factorization.
12003121313112 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 5619438915 (or 5619438911 counting only the distinct ones).
The product of its (nonzero) digits is 216, while the sum is 21.
Adding to 12003121313112 its reverse (21131312130021), we get a palindrome (33134433443133).
The spelling of 12003121313112 in words is "twelve trillion, three billion, one hundred twenty-one million, three hundred thirteen thousand, one hundred twelve".
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