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120031413 = 340010471
BaseRepresentation
bin1110010011110…
…00100010110101
322100212020010220
413021320202311
5221212001123
615524404553
72655151545
oct711704265
9270766126
10120031413
1161833417
1234246759
131bb38308
1411d27325
15a80ece3
hex72788b5

120031413 has 4 divisors (see below), whose sum is σ = 160041888. Its totient is φ = 80020940.

The previous prime is 120031409. The next prime is 120031421. The reversal of 120031413 is 314130021.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 120031413 - 22 = 120031409 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 120031392 and 120031401.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (120031403) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 20005233 + ... + 20005238.

It is an arithmetic number, because the mean of its divisors is an integer number (40010472).

Almost surely, 2120031413 is an apocalyptic number.

It is an amenable number.

120031413 is a deficient number, since it is larger than the sum of its proper divisors (40010475).

120031413 is an equidigital number, since it uses as much as digits as its factorization.

120031413 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 40010474.

The product of its (nonzero) digits is 72, while the sum is 15.

The square root of 120031413 is about 10955.8848570072. The cubic root of 120031413 is about 493.2854506221.

Adding to 120031413 its reverse (314130021), we get a palindrome (434161434).

The spelling of 120031413 in words is "one hundred twenty million, thirty-one thousand, four hundred thirteen".

Divisors: 1 3 40010471 120031413