12003233131 has 4 divisors (see below), whose sum is σ = 12003732000. Its totient is φ = 12002734264.

The previous prime is 12003233119. The next prime is 12003233149. The reversal of 12003233131 is 13133230021.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 12003233131 - 2²³ = 11994844523 is a prime.

It is a super-2 number, since 2×12003233131² (a number of 21 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 12003233099 and 12003233108.

It is not an unprimeable number, because it can be changed into a prime (12003233531) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 211411 + ... + 262108.

It is an arithmetic number, because the mean of its divisors is an integer number (3000933000).

Almost surely, 2^12003233131 is an apocalyptic number.

12003233131 is a deficient number, since it is larger than the sum of its proper divisors (498869).

12003233131 is an equidigital number, since it uses as much as digits as its factorization.

12003233131 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 498868.

The product of its (nonzero) digits is 324, while the sum is 19.

Adding to 12003233131 its reverse (13133230021), we get a palindrome (25136463152).

The spelling of 12003233131 in words is "twelve billion, three million, two hundred thirty-three thousand, one hundred thirty-one".