Base | Representation |
---|---|
bin | 10001011101111000111… |
… | …001110110001010001111 |
3 | 11020202020122221112120011 |
4 | 101131320321312022033 |
5 | 124131231010234201 |
6 | 2315231003334051 |
7 | 152502104153200 |
oct | 21357071661217 |
9 | 4222218845504 |
10 | 1200324305551 |
11 | 423066861708 |
12 | 17476a221327 |
13 | 89261845897 |
14 | 4214b6275a7 |
15 | 213533eb151 |
hex | 11778e7628f |
1200324305551 has 12 divisors (see below), whose sum is σ = 1396319689848. Its totient is φ = 1028831669712.
The previous prime is 1200324305549. The next prime is 1200324305567. The reversal of 1200324305551 is 1555034230021.
It is not a de Polignac number, because 1200324305551 - 21 = 1200324305549 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1200324305501) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 3225505 + ... + 3578341.
It is an arithmetic number, because the mean of its divisors is an integer number (116359974154).
Almost surely, 21200324305551 is an apocalyptic number.
1200324305551 is a deficient number, since it is larger than the sum of its proper divisors (195995384297).
1200324305551 is an equidigital number, since it uses as much as digits as its factorization.
1200324305551 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 422278 (or 422271 counting only the distinct ones).
The product of its (nonzero) digits is 18000, while the sum is 31.
Adding to 1200324305551 its reverse (1555034230021), we get a palindrome (2755358535572).
The spelling of 1200324305551 in words is "one trillion, two hundred billion, three hundred twenty-four million, three hundred five thousand, five hundred fifty-one".
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