Base | Representation |
---|---|
bin | 11011010010101101011101… |
… | …000010101101011111100110 |
3 | 120202000001011222201001102201 |
4 | 123102231131002231133212 |
5 | 111213110102033404110 |
6 | 1103142223210525114 |
7 | 34166045635521124 |
oct | 3322553502553746 |
9 | 522001158631381 |
10 | 120033012013030 |
11 | 35278795033206 |
12 | 11567250a3679a |
13 | 51c90ab8211ac |
14 | 218d8b352a914 |
15 | dd25028e7b3a |
hex | 6d2b5d0ad7e6 |
120033012013030 has 32 divisors (see below), whose sum is σ = 217687551922944. Its totient is φ = 47652106809216.
The previous prime is 120033012013001. The next prime is 120033012013043. The reversal of 120033012013030 is 30310210330021.
It is a junction number, because it is equal to n+sod(n) for n = 120033012012989 and 120033012013007.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 42940657 + ... + 45650476.
It is an arithmetic number, because the mean of its divisors is an integer number (6802735997592).
Almost surely, 2120033012013030 is an apocalyptic number.
120033012013030 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
120033012013030 is a deficient number, since it is larger than the sum of its proper divisors (97654539909914).
120033012013030 is a wasteful number, since it uses less digits than its factorization.
120033012013030 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 88592160.
The product of its (nonzero) digits is 324, while the sum is 19.
Adding to 120033012013030 its reverse (30310210330021), we get a palindrome (150343222343051).
The spelling of 120033012013030 in words is "one hundred twenty trillion, thirty-three billion, twelve million, thirteen thousand, thirty".
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