Base | Representation |
---|---|
bin | 11011010010101101110110… |
… | …101100100000110010100000 |
3 | 120202000002021222120001100012 |
4 | 123102231312230200302200 |
5 | 111213111442223321230 |
6 | 1103142334023344052 |
7 | 34166062412666621 |
oct | 3322556654406240 |
9 | 522002258501305 |
10 | 120033442401440 |
11 | 35278995a74407 |
12 | 11567350bb2028 |
13 | 51c9149a424a9 |
14 | 218d914761a48 |
15 | dd252a5b0395 |
hex | 6d2b76b20ca0 |
120033442401440 has 24 divisors (see below), whose sum is σ = 283579007673780. Its totient is φ = 48013376960512.
The previous prime is 120033442401421. The next prime is 120033442401503. The reversal of 120033442401440 is 44104244330021.
It can be written as a sum of positive squares in 2 ways, for example, as 119818506314896 + 214936086544 = 10946164^2 + 463612^2 .
It is a super-2 number, since 2×1200334424014402 (a number of 29 digits) contains 22 as substring.
It is a Harshad number since it is a multiple of its sum of digits (32).
It is a junction number, because it is equal to n+sod(n) for n = 120033442401397 and 120033442401406.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 375104507345 + ... + 375104507664.
Almost surely, 2120033442401440 is an apocalyptic number.
120033442401440 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
120033442401440 is an abundant number, since it is smaller than the sum of its proper divisors (163545565272340).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
120033442401440 is an equidigital number, since it uses as much as digits as its factorization.
120033442401440 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 750209015024 (or 750209015016 counting only the distinct ones).
The product of its (nonzero) digits is 36864, while the sum is 32.
Adding to 120033442401440 its reverse (44104244330021), we get a palindrome (164137686731461).
The spelling of 120033442401440 in words is "one hundred twenty trillion, thirty-three billion, four hundred forty-two million, four hundred one thousand, four hundred forty".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.073 sec. • engine limits •