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12003432241135 = 53077117801757
BaseRepresentation
bin1010111010101100010001…
…0100001001011111101111
31120111111221211110000111111
42232223010110021133233
53033131012123204020
641310144534532451
72346135145411306
oct256530424113757
946444854400444
1012003432241135
113908699631425
12141a419207127
13690bc37c37ba
142d6d7d77d43d
1515c3843e5d5a
hexaeac45097ef

12003432241135 has 8 divisors (see below), whose sum is σ = 14404167346176. Its totient is φ = 9602713355040.

The previous prime is 12003432241111. The next prime is 12003432241193. The reversal of 12003432241135 is 53114223430021.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 12003432241135 - 227 = 12003298023407 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 12003432241097 and 12003432241106.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 2362324 + ... + 5439433.

It is an arithmetic number, because the mean of its divisors is an integer number (1800520918272).

Almost surely, 212003432241135 is an apocalyptic number.

12003432241135 is a deficient number, since it is larger than the sum of its proper divisors (2400735105041).

12003432241135 is an equidigital number, since it uses as much as digits as its factorization.

12003432241135 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 8109473.

The product of its (nonzero) digits is 17280, while the sum is 31.

Adding to 12003432241135 its reverse (53114223430021), we get a palindrome (65117655671156).

The spelling of 12003432241135 in words is "twelve trillion, three billion, four hundred thirty-two million, two hundred forty-one thousand, one hundred thirty-five".

Divisors: 1 5 307711 1538555 7801757 39008785 2400686448227 12003432241135