Base | Representation |
---|---|
bin | 1010111010101100010001… |
… | …0100001001011111101111 |
3 | 1120111111221211110000111111 |
4 | 2232223010110021133233 |
5 | 3033131012123204020 |
6 | 41310144534532451 |
7 | 2346135145411306 |
oct | 256530424113757 |
9 | 46444854400444 |
10 | 12003432241135 |
11 | 3908699631425 |
12 | 141a419207127 |
13 | 690bc37c37ba |
14 | 2d6d7d77d43d |
15 | 15c3843e5d5a |
hex | aeac45097ef |
12003432241135 has 8 divisors (see below), whose sum is σ = 14404167346176. Its totient is φ = 9602713355040.
The previous prime is 12003432241111. The next prime is 12003432241193. The reversal of 12003432241135 is 53114223430021.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 12003432241135 - 227 = 12003298023407 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 12003432241097 and 12003432241106.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 2362324 + ... + 5439433.
It is an arithmetic number, because the mean of its divisors is an integer number (1800520918272).
Almost surely, 212003432241135 is an apocalyptic number.
12003432241135 is a deficient number, since it is larger than the sum of its proper divisors (2400735105041).
12003432241135 is an equidigital number, since it uses as much as digits as its factorization.
12003432241135 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 8109473.
The product of its (nonzero) digits is 17280, while the sum is 31.
Adding to 12003432241135 its reverse (53114223430021), we get a palindrome (65117655671156).
The spelling of 12003432241135 in words is "twelve trillion, three billion, four hundred thirty-two million, two hundred forty-one thousand, one hundred thirty-five".
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