Base | Representation |
---|---|
bin | 1010111010101110110110… |
… | …0000111100001110010111 |
3 | 1120111120202000002121012211 |
4 | 2232223231200330032113 |
5 | 3033133421101214003 |
6 | 41310341310054251 |
7 | 2346161240602156 |
oct | 256535540741627 |
9 | 46446660077184 |
10 | 12004123460503 |
11 | 3908a138237a9 |
12 | 141a5907aa387 |
13 | 690ca3a7a345 |
14 | 2d70074ad59d |
15 | 15c3c4e3196d |
hex | aeaed83c397 |
12004123460503 has 2 divisors, whose sum is σ = 12004123460504. Its totient is φ = 12004123460502.
The previous prime is 12004123460501. The next prime is 12004123460509. The reversal of 12004123460503 is 30506432140021.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 12004123460503 - 21 = 12004123460501 is a prime.
Together with 12004123460501, it forms a pair of twin primes.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (12004123460501) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6002061730251 + 6002061730252.
It is an arithmetic number, because the mean of its divisors is an integer number (6002061730252).
Almost surely, 212004123460503 is an apocalyptic number.
12004123460503 is a deficient number, since it is larger than the sum of its proper divisors (1).
12004123460503 is an equidigital number, since it uses as much as digits as its factorization.
12004123460503 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 17280, while the sum is 31.
The spelling of 12004123460503 in words is "twelve trillion, four billion, one hundred twenty-three million, four hundred sixty thousand, five hundred three".
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