1200420202021 has 4 divisors (see below), whose sum is σ = 1220766307200. Its totient is φ = 1180074096844.

The previous prime is 1200420201997. The next prime is 1200420202039. The reversal of 1200420202021 is 1202020240021.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1200420202021 - 2¹¹ = 1200420199973 is a prime.

It is a super-2 number, since 2×1200420202021² (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1200420201986 and 1200420202004.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1200420202081) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 10173052501 + ... + 10173052618.

It is an arithmetic number, because the mean of its divisors is an integer number (305191576800).

Almost surely, 2^{1200420202021} is an apocalyptic number.

It is an amenable number.

1200420202021 is a deficient number, since it is larger than the sum of its proper divisors (20346105179).

1200420202021 is an equidigital number, since it uses as much as digits as its factorization.

1200420202021 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 20346105178.

The product of its (nonzero) digits is 128, while the sum is 16.

Adding to 1200420202021 its reverse (1202020240021), we get a palindrome (2402440442042).

The spelling of 1200420202021 in words is "one trillion, two hundred billion, four hundred twenty million, two hundred two thousand, twenty-one".