120042130021 has 4 divisors (see below), whose sum is σ = 130955050944. Its totient is φ = 109129209100.

The previous prime is 120042130003. The next prime is 120042130027. The reversal of 120042130021 is 120031240021.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 120042130021 - 2¹¹ = 120042127973 is a prime.

It is a super-2 number, since 2×120042130021² (a number of 23 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 120042129977 and 120042130004.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (120042130027) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5456460445 + ... + 5456460466.

It is an arithmetic number, because the mean of its divisors is an integer number (32738762736).

Almost surely, 2^120042130021 is an apocalyptic number.

120042130021 is a gapful number since it is divisible by the number (11) formed by its first and last digit.

It is an amenable number.

120042130021 is a deficient number, since it is larger than the sum of its proper divisors (10912920923).

120042130021 is a wasteful number, since it uses less digits than its factorization.

120042130021 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 10912920922.

The product of its (nonzero) digits is 96, while the sum is 16.

Adding to 120042130021 its reverse (120031240021), we get a palindrome (240073370042).

Subtracting from 120042130021 its reverse (120031240021), we obtain a square (10890000 = 3300²).

The spelling of 120042130021 in words is "one hundred twenty billion, forty-two million, one hundred thirty thousand, twenty-one".