Base | Representation |
---|---|
bin | 10110010111000001… |
… | …00010101011100111 |
3 | 1010222121002120200022 |
4 | 23023200202223213 |
5 | 144041041140403 |
6 | 5303100305355 |
7 | 603322233362 |
oct | 131340425347 |
9 | 33877076608 |
10 | 12004240103 |
11 | 5100098299 |
12 | 23b024225b |
13 | 1193cba76b |
14 | 81c4030d9 |
15 | 4a3d0bd38 |
hex | 2cb822ae7 |
12004240103 has 2 divisors, whose sum is σ = 12004240104. Its totient is φ = 12004240102.
The previous prime is 12004240099. The next prime is 12004240111. The reversal of 12004240103 is 30104240021.
12004240103 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 12004240103 - 22 = 12004240099 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (12004240403) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6002120051 + 6002120052.
It is an arithmetic number, because the mean of its divisors is an integer number (6002120052).
Almost surely, 212004240103 is an apocalyptic number.
12004240103 is a deficient number, since it is larger than the sum of its proper divisors (1).
12004240103 is an equidigital number, since it uses as much as digits as its factorization.
12004240103 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 192, while the sum is 17.
Adding to 12004240103 its reverse (30104240021), we get a palindrome (42108480124).
The spelling of 12004240103 in words is "twelve billion, four million, two hundred forty thousand, one hundred three".
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