Search a number
-
+
120043000023 = 340014333341
BaseRepresentation
bin110111111001100011…
…1101101000011010111
3102110212000002020102220
41233303013231003113
53431322002000043
6131051430033423
711446530443622
oct1576307550327
9373760066386
10120043000023
1146a01164731
121b3221a8873
13b42109157b
145b4ad3adb9
1531c8b4b483
hex1bf31ed0d7

120043000023 has 4 divisors (see below), whose sum is σ = 160057333368. Its totient is φ = 80028666680.

The previous prime is 120043000003. The next prime is 120043000037. The reversal of 120043000023 is 320000340021.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 120043000023 - 217 = 120042868951 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 120042999966 and 120043000011.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (120043000003) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 20007166668 + ... + 20007166673.

It is an arithmetic number, because the mean of its divisors is an integer number (40014333342).

Almost surely, 2120043000023 is an apocalyptic number.

120043000023 is a deficient number, since it is larger than the sum of its proper divisors (40014333345).

120043000023 is an equidigital number, since it uses as much as digits as its factorization.

120043000023 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 40014333344.

The product of its (nonzero) digits is 144, while the sum is 15.

Adding to 120043000023 its reverse (320000340021), we get a palindrome (440043340044).

The spelling of 120043000023 in words is "one hundred twenty billion, forty-three million, twenty-three", and thus it is an aban number.

Divisors: 1 3 40014333341 120043000023