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12004324751 is a prime number
BaseRepresentation
bin10110010111000001…
…10111010110001111
31010222121020212210102
423023200313112033
5144041101343001
65303102201315
7603323035226
oct131340672617
933877225712
1012004324751
115100145951
1223b028323b
13119401a153
1481c425cbd
154a3d26e6b
hex2cb83758f

12004324751 has 2 divisors, whose sum is σ = 12004324752. Its totient is φ = 12004324750.

The previous prime is 12004324741. The next prime is 12004324753. The reversal of 12004324751 is 15742340021.

It is a strong prime.

It is an emirp because it is prime and its reverse (15742340021) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 12004324751 - 214 = 12004308367 is a prime.

Together with 12004324753, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (12004324753) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6002162375 + 6002162376.

It is an arithmetic number, because the mean of its divisors is an integer number (6002162376).

Almost surely, 212004324751 is an apocalyptic number.

12004324751 is a deficient number, since it is larger than the sum of its proper divisors (1).

12004324751 is an equidigital number, since it uses as much as digits as its factorization.

12004324751 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 6720, while the sum is 29.

Adding to 12004324751 its reverse (15742340021), we get a palindrome (27746664772).

The spelling of 12004324751 in words is "twelve billion, four million, three hundred twenty-four thousand, seven hundred fifty-one".