12005113 has 4 divisors (see below), whose sum is σ = 12078928. Its totient is φ = 11931300.

The previous prime is 12005099. The next prime is 12005141. The reversal of 12005113 is 31150021.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 31150021 = 7 ⋅4450003.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-12005113 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 12005093 and 12005102.

It is not an unprimeable number, because it can be changed into a prime (12005813) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 36663 + ... + 36988.

It is an arithmetic number, because the mean of its divisors is an integer number (3019732).

Almost surely, 2^12005113 is an apocalyptic number.

It is an amenable number.

12005113 is a deficient number, since it is larger than the sum of its proper divisors (73815).

12005113 is an equidigital number, since it uses as much as digits as its factorization.

12005113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 73814.

The product of its (nonzero) digits is 30, while the sum is 13.

The square root of 12005113 is about 3464.8395345239. The cubic root of 12005113 is about 228.9753601376.

Adding to 12005113 its reverse (31150021), we get a palindrome (43155134).

The spelling of 12005113 in words is "twelve million, five thousand, one hundred thirteen".