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120053345143 = 1731227805209
BaseRepresentation
bin110111111001110111…
…1001010101101110111
3102110212201112211021111
41233303233022231313
53431332124021033
6131052435455451
711450014411414
oct1576357125567
9373781484244
10120053345143
1146a06a90116
121b325757587
13b423274244
145b4c47110b
1531c99e17cd
hex1bf3bcab77

120053345143 has 8 divisors (see below), whose sum is σ = 131215800960. Its totient is φ = 109346499840.

The previous prime is 120053345131. The next prime is 120053345189. The reversal of 120053345143 is 341543350021.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-120053345143 is a prime.

It is a Harshad number since it is a multiple of its sum of digits (31).

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (120053345123) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 113902078 + ... + 113903131.

It is an arithmetic number, because the mean of its divisors is an integer number (16401975120).

Almost surely, 2120053345143 is an apocalyptic number.

120053345143 is a deficient number, since it is larger than the sum of its proper divisors (11162455817).

120053345143 is a wasteful number, since it uses less digits than its factorization.

120053345143 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 227805257.

The product of its (nonzero) digits is 21600, while the sum is 31.

Adding to 120053345143 its reverse (341543350021), we get a palindrome (461596695164).

The spelling of 120053345143 in words is "one hundred twenty billion, fifty-three million, three hundred forty-five thousand, one hundred forty-three".

Divisors: 1 17 31 527 227805209 3872688553 7061961479 120053345143