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12005343445 = 52401068689
BaseRepresentation
bin10110010111001001…
…10000000011010101
31010222200011122011211
423023210300003111
5144041331442240
65303140101421
7603334510204
oct131344600325
933880148154
1012005343445
115100781247
1223b0694871
1311942b5a24
1481c60d23b
154a3e78bea
hex2cb9300d5

12005343445 has 4 divisors (see below), whose sum is σ = 14406412140. Its totient is φ = 9604274752.

The previous prime is 12005343437. The next prime is 12005343521. The reversal of 12005343445 is 54434350021.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 8603304516 + 3402038929 = 92754^2 + 58327^2 .

It is a cyclic number.

It is not a de Polignac number, because 12005343445 - 23 = 12005343437 is a prime.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1200534340 + ... + 1200534349.

It is an arithmetic number, because the mean of its divisors is an integer number (3601603035).

Almost surely, 212005343445 is an apocalyptic number.

It is an amenable number.

12005343445 is a deficient number, since it is larger than the sum of its proper divisors (2401068695).

12005343445 is an equidigital number, since it uses as much as digits as its factorization.

12005343445 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2401068694.

The product of its (nonzero) digits is 28800, while the sum is 31.

Adding to 12005343445 its reverse (54434350021), we get a palindrome (66439693466).

The spelling of 12005343445 in words is "twelve billion, five million, three hundred forty-three thousand, four hundred forty-five".

Divisors: 1 5 2401068689 12005343445