Base | Representation |
---|---|
bin | 10001011110000101110… |
… | …001001111110111000011 |
3 | 11020202210201002211210110 |
4 | 101132011301033313003 |
5 | 124132201234432311 |
6 | 2315304234002403 |
7 | 152510334642636 |
oct | 21360561176703 |
9 | 4222721084713 |
10 | 1200540155331 |
11 | 42316768a860 |
12 | 17480a576403 |
13 | 8929748c24a |
14 | 4216c173c1d |
15 | 213673368a6 |
hex | 11785c4fdc3 |
1200540155331 has 16 divisors (see below), whose sum is σ = 1750729294080. Its totient is φ = 725729649120.
The previous prime is 1200540155263. The next prime is 1200540155351. The reversal of 1200540155331 is 1335510450021.
It is not a de Polignac number, because 1200540155331 - 219 = 1200539631043 is a prime.
It is a super-2 number, since 2×12005401553312 (a number of 25 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (1200540155351) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 46748095 + ... + 46773768.
It is an arithmetic number, because the mean of its divisors is an integer number (109420580880).
Almost surely, 21200540155331 is an apocalyptic number.
1200540155331 is a gapful number since it is divisible by the number (11) formed by its first and last digit.
1200540155331 is a deficient number, since it is larger than the sum of its proper divisors (550189138749).
1200540155331 is a wasteful number, since it uses less digits than its factorization.
1200540155331 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 93522266.
The product of its (nonzero) digits is 9000, while the sum is 30.
The spelling of 1200540155331 in words is "one trillion, two hundred billion, five hundred forty million, one hundred fifty-five thousand, three hundred thirty-one".
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