Base | Representation |
---|---|
bin | 11011010011000001011110… |
… | …011101000100000111101111 |
3 | 120202002002200020222010120202 |
4 | 123103001132131010013233 |
5 | 111213433114144111101 |
6 | 1103200140350504115 |
7 | 34200436455116153 |
oct | 3323013635040757 |
9 | 522062606863522 |
10 | 120054510535151 |
11 | 35286917423065 |
12 | 1156b45080503b |
13 | 51cb1267c14ba |
14 | 219095284d063 |
15 | dd2d5eeba36b |
hex | 6d305e7441ef |
120054510535151 has 2 divisors, whose sum is σ = 120054510535152. Its totient is φ = 120054510535150.
The previous prime is 120054510535139. The next prime is 120054510535153. The reversal of 120054510535151 is 151535015450021.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 120054510535151 - 26 = 120054510535087 is a prime.
Together with 120054510535153, it forms a pair of twin primes.
It is a Chen prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (120054510535153) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60027255267575 + 60027255267576.
It is an arithmetic number, because the mean of its divisors is an integer number (60027255267576).
Almost surely, 2120054510535151 is an apocalyptic number.
120054510535151 is a deficient number, since it is larger than the sum of its proper divisors (1).
120054510535151 is an equidigital number, since it uses as much as digits as its factorization.
120054510535151 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 75000, while the sum is 38.
Adding to 120054510535151 its reverse (151535015450021), we get a palindrome (271589525985172).
The spelling of 120054510535151 in words is "one hundred twenty trillion, fifty-four billion, five hundred ten million, five hundred thirty-five thousand, one hundred fifty-one".
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