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120100100121341 is a prime number
BaseRepresentation
bin11011010011101011111011…
…110011100010001011111101
3120202020110100110211001211222
4123103223323303202023331
5111220210001112340331
61103233120241523125
734203642304161464
oct3323537363421375
9522213313731758
10120100100121341
11352a4191573a1a
12115782546434a5
1352025108c31c2
142192c395139db
15dd412c56ab7b
hex6d3afbce22fd

120100100121341 has 2 divisors, whose sum is σ = 120100100121342. Its totient is φ = 120100100121340.

The previous prime is 120100100121257. The next prime is 120100100121359. The reversal of 120100100121341 is 143121001001021.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 85581537558841 + 34518562562500 = 9251029^2 + 5875250^2 .

It is a cyclic number.

It is not a de Polignac number, because 120100100121341 - 222 = 120100095927037 is a prime.

It is a super-2 number, since 2×1201001001213412 (a number of 29 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (120100100121941) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60050050060670 + 60050050060671.

It is an arithmetic number, because the mean of its divisors is an integer number (60050050060671).

Almost surely, 2120100100121341 is an apocalyptic number.

It is an amenable number.

120100100121341 is a deficient number, since it is larger than the sum of its proper divisors (1).

120100100121341 is an equidigital number, since it uses as much as digits as its factorization.

120100100121341 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 48, while the sum is 17.

Adding to 120100100121341 its reverse (143121001001021), we get a palindrome (263221101122362).

The spelling of 120100100121341 in words is "one hundred twenty trillion, one hundred billion, one hundred million, one hundred twenty-one thousand, three hundred forty-one".