Base | Representation |
---|---|
bin | 110111111011010010… |
… | …1011010110001110111 |
3 | 102111000001110002121222 |
4 | 1233312211122301313 |
5 | 3431431341334033 |
6 | 131101303500555 |
7 | 11451134454143 |
oct | 1576645326167 |
9 | 374001402558 |
10 | 120101121143 |
11 | 46a30a51a13 |
12 | 1b33975775b |
13 | b430131273 |
14 | 5b5494a223 |
15 | 31cdccc598 |
hex | 1bf695ac77 |
120101121143 has 2 divisors, whose sum is σ = 120101121144. Its totient is φ = 120101121142.
The previous prime is 120101121109. The next prime is 120101121169. The reversal of 120101121143 is 341121101021.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 120101121143 - 232 = 115806153847 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (120101121643) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60050560571 + 60050560572.
It is an arithmetic number, because the mean of its divisors is an integer number (60050560572).
Almost surely, 2120101121143 is an apocalyptic number.
120101121143 is a deficient number, since it is larger than the sum of its proper divisors (1).
120101121143 is an equidigital number, since it uses as much as digits as its factorization.
120101121143 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 48, while the sum is 17.
Adding to 120101121143 its reverse (341121101021), we get a palindrome (461222222164).
The spelling of 120101121143 in words is "one hundred twenty billion, one hundred one million, one hundred twenty-one thousand, one hundred forty-three".
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