Base | Representation |
---|---|
bin | 10001011110100001110… |
… | …110001101111011111111 |
3 | 11020211000112111102100022 |
4 | 101132201312031323333 |
5 | 124134132333021343 |
6 | 2315423102322355 |
7 | 152525114634653 |
oct | 21364166157377 |
9 | 4224015442308 |
10 | 1201011220223 |
11 | 423389583891 |
12 | 1749202893bb |
13 | 89340c52c79 |
14 | 421b4956a63 |
15 | 21393886568 |
hex | 117a1d8deff |
1201011220223 has 2 divisors, whose sum is σ = 1201011220224. Its totient is φ = 1201011220222.
The previous prime is 1201011220217. The next prime is 1201011220247. The reversal of 1201011220223 is 3220221101021.
It is a weak prime.
It is an emirp because it is prime and its reverse (3220221101021) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 1201011220223 - 234 = 1183831351039 is a prime.
It is a super-2 number, since 2×12010112202232 (a number of 25 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1201011220273) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 600505610111 + 600505610112.
It is an arithmetic number, because the mean of its divisors is an integer number (600505610112).
Almost surely, 21201011220223 is an apocalyptic number.
1201011220223 is a deficient number, since it is larger than the sum of its proper divisors (1).
1201011220223 is an equidigital number, since it uses as much as digits as its factorization.
1201011220223 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 96, while the sum is 17.
Adding to 1201011220223 its reverse (3220221101021), we get a palindrome (4421232321244).
The spelling of 1201011220223 in words is "one trillion, two hundred one billion, eleven million, two hundred twenty thousand, two hundred twenty-three".
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