Base | Representation |
---|---|
bin | 1010111011000101001100… |
… | …0000001010100111010100 |
3 | 1120112011012222201212101012 |
4 | 2232301103000022213110 |
5 | 3033233212001041040 |
6 | 41313212400351352 |
7 | 2346462666026513 |
oct | 256612300124724 |
9 | 46464188655335 |
10 | 12010121112020 |
11 | 39105112a0099 |
12 | 141b785315558 |
13 | 69171b503175 |
14 | 2d7415c6a67a |
15 | 15c626753865 |
hex | aec5300a9d4 |
12010121112020 has 192 divisors, whose sum is σ = 26915589550080. Its totient is φ = 4495226803200.
The previous prime is 12010121111983. The next prime is 12010121112037. The reversal of 12010121112020 is 2021112101021.
It is a junction number, because it is equal to n+sod(n) for n = 12010121111986 and 12010121112004.
It is a congruent number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 2211398705 + ... + 2211404135.
It is an arithmetic number, because the mean of its divisors is an integer number (140185362240).
Almost surely, 212010121112020 is an apocalyptic number.
12010121112020 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 12010121112020, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (13457794775040).
12010121112020 is an abundant number, since it is smaller than the sum of its proper divisors (14905468438060).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
12010121112020 is a wasteful number, since it uses less digits than its factorization.
12010121112020 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 6646 (or 6644 counting only the distinct ones).
The product of its (nonzero) digits is 16, while the sum is 14.
Adding to 12010121112020 its reverse (2021112101021), we get a palindrome (14031233213041).
The spelling of 12010121112020 in words is "twelve trillion, ten billion, one hundred twenty-one million, one hundred twelve thousand, twenty".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.080 sec. • engine limits •